Question

If displacement of a particle is given as $x=t^3-2t^2$, then average acceleration from $0$ to $2$ seconds is

• A. $2m/s^2$
• B. $4m/s^2$
• C. $8m/s^2$
• D. $1m/s^2$

Answer 1

The correct option is A $2m/s^2$

$v=\frac{dx}{dt}=3t^2-4t$
$v_{t=2}=4m/s$ & $v_{t=0}=0m/s$
$<a>=\frac{\Delta V}{\Delta t}=\frac{4-0}{2}=2m/s^2$