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Question

If 1+14+19+116+...=π26 then the value of 14+116+136+164+... is equals

A
π26
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B
π212
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C
π28
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D
π224
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Solution

The correct option is D π224
Sum = 14 + 116 + 136 + 164 + .........
Taking 14 common, we get
= 14 ( 1 + 14 + 19 + 116 + .........)
= 14. π26 = π224

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