If 1-i1-2i1-3i-1-ni- - -i- then - 2- 2 equals

The correct option is C 2· 5· 10...(n^2+1) Given α iβ = ( 1+i ) ( 1 2i )... ( 1 ni ) ∴ | α iβ nbsp; |^2= [ √( ( 1+1^2 ) ( 1+2^2 ) ( 1+3 ...

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Properties of Conjugate of a Complex Number

If 1+i1-2i1...

Question

If $(1 + i) (1 - 2 i) (1 - 3 i) . . . (1 - n i) = α - i β$ then $α^{2} + β^{2}$ equals

1 \cdot 2 \cdot 3... n

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1^{2} \cdot 2^{2} \cdot 3^{2} . . . n^{2}

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1^{2} + 2^{2} + 3^{2} + 4^{2} + . . . n^{2}

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2 \cdot 5 \cdot 10... (n^{2} + 1)

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Solution

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Similar questions

(1 - i) (1 + 2 i) (1 + 3 i) . . . . (1 + n i) = α + i β

2 \cdot 5 \cdot 10 . . . . (1 + n^{2}) =

(1 + i) (1 + 2 i) (1 + 3 i) . . . . (1 + n i) = α + i β

2.5.10 . . . (1 + n^{2}) =

1 + 2 + 3 + 4 + . . . . . + n = ?

1 + 2 + 3 + 4 + . . . . . + (n - 1) = ?

1 + 1 + 1 + 1 + . . . . . + n = ?

1 + 1 + 1 + 1 + . . . . . . + (n - 1) = ?

1^{2} + 2^{2} + 3^{2} + 4^{2} + . . . . + n^{2} = ?

1^{2} + 2^{2} + 3^{2} + 4^{2} + . . . . + {(n - 1)}^{2} = ?

(1 - i) (1 - 2 i) (1 - 3 i) . . . (1 - n i) = x - i y

2 \cdot 5 \cdot 10..... (1 + n^{2}) =

1^{2} + 1 + 2^{2} + 2 + 3^{2} + 3 + \dots . . + n^{2} + n =

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