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Question

If 1,ω,ω2 are cube roots of unity then ∣ ∣ ∣1ωnω2nωnω2n1ω2n1ωn∣ ∣ ∣ equals

A
1
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B
ω
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C
ω2
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D
0
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Solution

The correct option is B 0
Since, 1,ω,ω2 are the cube roots of unity.
ω3=1
ω3n=1
∣ ∣ ∣1ωnω2nωnω2n1ω2n1ωn∣ ∣ ∣
1(ω3n1)ωn(ω2nω2n)+ω2n(ωnω4n)=0

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