If 1- 2-32-4- 3-712-4- 7-1128- then 5- 1 -

The correct option is C 65the rule is : #160; a× b=( a+b ) ( ab ) #160; ∴ 1× 2=( 1+2 ) ( 1× 2 ) =32 etc. ⇒ 5× 1=( 5+1 ) ( 5× 1 ) =65 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Purely Real

If 1× 2=32;...

Question

If $1 \times 2 = 32; 4 \times 3 = 712; 4 \times 7 = 1128$ , then $5 \times 1$ =?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\times

\times

\times

\times

S_{n} = \frac{1}{1 \cdot 3 \cdot 5} + \frac{1}{3 \cdot 5 \cdot 7} + \frac{1}{5 \cdot 7 \cdot 9} \dots

24 S_{\infty} =

S_{n} = \frac{1}{1 \cdot 3 \cdot 5} + \frac{1}{3 \cdot 5 \cdot 7} + \frac{1}{5 \cdot 7 \cdot 9} \dots

24 S_{\infty} =

U = 1, 2, 3, 4, 5, 6, 7, A = 1, 2, 3, 4, 5

B = 1, 3, 5, 7

A^{'} - B^{'}

\frac{x}{2} = \frac{1}{\sqrt{7} + \sqrt{5}}, \frac{y}{2} = \frac{1}{\sqrt{5} + \sqrt{3}}, \frac{- z}{4} = \frac{1}{\sqrt{3} + \sqrt{7}},

x^{3} + y^{3} + z^{3} - 2 x y z

Join BYJU'S Learning Program