Question

If $15\frac{2}{3}\times 3\frac{1}{6}+6\frac{1}{3}=11\frac{7}{18}+x$, then the value of $x$ is ______ .

• A. $39\frac{5}{9}$
• B. $137\frac{4}{9}$
• C. $29\frac{7}{9}$
• D. $44\frac{5}{9}$

Answer 1

The correct option is D $44\frac{5}{9}$

$15\frac{2}{3}\times 3\frac{1}{6}+6\frac{1}{3}=11\frac{7}{18}+x$
Or $\frac{47}{3}\times \frac{19}{6}+\frac{19}{3}=\frac{205}{18}+x$
Or $\frac{893}{18}+\frac{19}{3}=\frac{205}{18}+x$
Or 893+114=205+18x
Or 18x=893+114-205=$\frac{802}{18}=44\frac{5}{9}$