If $1960 = 2^{a} . 5^{b} . 7^{c}$ , find the value of $a$ .

2

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3

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5

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1

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Solution

The correct option is B $3$
Given, $1960 = 2^{a} . 5^{b} . 7^{c}$
Now,
$1960 = 2^{3} . 5^{1} . 7^{2}$
Thus, comparing the above two we get
$a = 3$ , $b = 1$ , $c = 2$ ,

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Similar questions

1960 =

2^{a} \cdot 5^{b} \cdot 7^{c}

2^{- a} \cdot 7^{b} \cdot 5^{- c}

If the point $P (a, 5)$ lies on the line $2 x - 3 y - 5 = 0$ , then find the value of $a$ .

If 2 a - 3 = 5

and 3 b + 1 = 2

then find the value of (3 b - 2 a) .

4725 = 3^{a} 5^{b} 7^{c}

2^{- a} 3^{b} 7^{c}

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