Question

If $2^{2^3}=j,2^{3^2}=k,3^{2^2}=\phi ,$ then

• A. $k=2j$
• B. $j<k$
• C. $\phi <k$
• D. All of these

Answer 1

The correct option is D All of these

$j=2^{2{}^3}$, $k=2^{3^2}$, $\phi =3^{2^2}$

$\Rightarrow$ $j=256,k=512,\phi =81$

$\Rightarrow$ Option A says $k=2j$, which is true because $j=256$, so $k=2\times 256=512$

$\Rightarrow$ Option B says $j<k$, which is true because value of $j$ is $255$ and value of $k$ is $512$

$\Rightarrow$ Option C says $\phi <k$, which is true because value of $\phi$ is $81$ and value of $k$ is $512$