if $2^{a} 2^{b} 2^{c}$ = 256 , then the average of the a, b, and c is

\frac{8}{3}

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\frac{256}{3}

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\frac{4}{3}

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Solution

The correct option is A $\frac{8}{3}$
Given, $2^{a} 2^{b} 2^{c} = 256$
$\Rightarrow 2^{a + b + c} = 2^{8}$
On equating the power, we get
$a + b + c = 8$
Now, average of a, b, c= $\frac{a + b + c}{3} = \frac{8}{3}$
Therefore, Option A is correct.

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