Question

If $2+\log x=\log 45-\log 2+\log 16-2\log 3$ and $x$ = $\frac{m}{10}$, then the value of $m$ is equal to

• A. $5$
• B. $8$
• C. $4$
• D. $2$

Answer 1

Answer: (C)

$4$

$2+\log x=\log 45-\log 2+\log 16-\log 92+\log x=\log \left(\frac{45\times 16}{9\times 2}\right)2+\log x=\log 40\text{Assuming base 10}\log x=\log 40-\log 100\log x=\log \frac{40}{100}=\log 0.40x=0.40$