If $2^{n} - 2^{n - 1} = 4$ , then the value of $n^{n}$ will be -

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\frac{3}{2}

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Solution

The correct option is D 27
$2^{n} - 2^{n - 1} = 4$
$∴ 2^{n - 1} (2 - 1) = 4$
$∴ 2^{n - 1} = 2^{2}$
$∴ n - 1 = 2$
$∴ n = 3$
$∴ n^{n} = 3^{3} = 27$

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