If $(28)^{2}$ is added to the square of a number, the answer so obtained is 1808. What is the number?

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Solution

The correct option is D 32
${(28)}^{2} + x^{2} = 1808$
$\Rightarrow x^{2} = 1808 - {(28)}^{2}$
$\Rightarrow x^{2} = 1808 - 784 = 1024$
$\Rightarrow x = \sqrt{1024} = 32$

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