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Question

If 2Q+3P=3PQ2R, express P in terms of Q and R. Find the value of P, when R=2 and Q=1.

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Solution

Given, 2Q+3P=3PQ2R
=>4RQ+6PR=3PQ
=>6PR3P=4RQQ
=>3P(2R1)=Q(4R+1)
=>3P(12R)=Q(4R+1)
=>P=Q(4R+1)3(12R)
When, R=2,Q=1, we have
=>P=1(4×(2)+1)3(12×(2))
=>P=715

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