If $3^{2 - {log}_{3} 5} = k$ ,then find 5k

Open in App

Solution

Given $3^{2 - {log}_{3} 5} = 3^{2} 3^{- {log}_{3} 5}$ $[∵ a^{m + n} = a^{m} . a^{n}]$
$= {9.3}^{{log}_{3} 5^{- 1}} = 9 \times 5^{- 1} = \frac{9}{5}$
$∴ k = \frac{9}{5}$
$5 k = 9$

Suggest Corrections

Similar questions

3^{2 - {log}_{3} 5}

{log}_{10} 1 = k

5 k

\sqrt[4]{81} - \sqrt[5]{32}

2

P (x) = 2 x^{2} - 3 x + 5 k

K

5 \div 3 \frac{4}{7}

\frac{2}{3}, k, \frac{5 k}{8}

k =

Join BYJU'S Learning Program