Question

If $3(4-\frac{2}{8}x)-12(1+3x)=9-\frac{8x}{4}$, find $x$.

• A. $\frac{36}{139}$
• B. $-\frac{36}{139}$
• C. $139$
• D. $36$

Answer 1

The correct option is B $-\frac{36}{139}$

Given, $3(4-\frac{2}{8}x)-12(1+3x)=9-\frac{8x}{4}$.

$⟹12-\frac{6}{8}x-12-36x=9-\frac{8x}{4}$ ...[By Distribution Law]

$⟹\frac{-6}{8}x-36x=9-\frac{8}{4}x$ ...[Simplifying].

Transposing $x$ terms to one side, we get,
$⟹-\frac{6x}{8}-36x+\frac{8}{4}x=9$.

Here, $8$ is the LCM, then we get,

$⟹\frac{-6x-36\times 8x+8\times 2x}{8}=9$

$⟹-288x-6x+16x=72$ ...[Multiplying by $8$ to both sides and simplifying]

$⟹-278x=72$

$⟹x=\frac{72}{-278}$

$⟹x=\frac{-36}{139}$.

Hence, option $B$ is correct.