If $3^{n} = 27$ , then $3^{n - 2}$ is:

3

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\frac{1}{3}

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\frac{1}{9}

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9

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Solution

The correct option is C $3$
$3^{n} = 27$

$\to 3^{n} = 3^{3}$

$∴$ $n = 3$ ...( using property of indices if $a^{m_{1}} = a^{m_{2}} ⟹ m_{1} = m_{2}$ )

Substituting values we get ,
$3^{n - 2} = 3^{3 - 2} = 3^{1} = 3$

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