If 3sinθ+5cosθ=5 then 5sinθ−3cosθ=
The correct option is B ±3
Let 5sinθ−3cosθ=x Then
Consider (3sinθ+5cosθ)2+(5sinθ−3cosθ)2=9(sin2θ+cos2θ)+25(cos2θ+sin2θ)
(3sinθ+5cosθ)2+(5sinθ−3cosθ)2 = 9 + 25 = 34 (sin2θ + cos2θ = 1)
∴x2+25 = 34
x2 = 9
x=±3