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Byju's Answer
Standard VI
Mathematics
Importance of Brackets
If 32× 41=1...
Question
If
32
×
41
=
15
;
51
×
34
=
46
;
41
×
52
=
37
, then
87
×
53
=
?
=?
A
68
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B
64
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C
85
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D
18
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E
42
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Solution
The correct option is
D
18
the logic is :
32
×
41
=
(
3
−
2
)
(
4
+
1
)
=
15
;
51
×
34
=
(
5
−
1
)
(
3
+
4
)
=
47
e
t
c
.
∴
87
×
53
=
(
8
−
7
)
(
5
+
3
)
=
18
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0
Similar questions
Q.
If 32
×
41=15; 51
×
34= 46; 41
×
52 = 37 then 87
×
53 = ?
Q.
If
A
=
⎡
⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢
⎣
2
3
1
3
7
3
1
2
3
2
5
3
4
3
2
3
⎤
⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥
⎦
and
B
=
⎡
⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢
⎣
2
5
1
5
7
5
3
5
2
5
6
5
1
4
5
2
5
⎤
⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥
⎦
, then compute
3
A
−
5
B
.
Q.
If
323
×
41
=
14323
,
137
×
72
=
27731
,
48
×
87
=
7884
then
34
×
75
=
?
Q.
If
323
×
41
=
14323
;
137
×
72
=
27731
and
48
×
87
=
7884
, then
34
×
75
=
?
Q.
Prepare a frequency table taking class intervals 20−24, 25−29, 30−34 and so on, from the following data:
21
20
55
39
48
46
36
54
42
30
29
42
32
40
34
31
35
37
52
44
39
45
37
33
51
53
52
46
43
47
41
26
52
48
25
34
37
33
36
27
54
36
41
33
23
39
28
44
45
38
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