Question

If
$5\frac{1}{6}-[1\frac{1}{5}+\{2\frac{3}{4}÷5\frac{1}{2}÷\chi -(\frac{5}{6}-\frac{2}{3})\}]=2\frac{61}{120}$
then the value of x is

• A. $\frac{4}{13}$
• B. $\frac{3}{13}$
• C. $\frac{4}{11}$
• D. $\frac{3}{11}$

Answer 1

Answer: (A)

$\frac{4}{13}$

Given
$\frac{31}{6}-[\frac{6}{5}+\{\frac{11}{4}\times \frac{2}{11}\times \frac{1}{x}-(\frac{5}{6}-\frac{2}{3})\}]=\frac{301}{120}$
$\Rightarrow \frac{31}{6}-[\frac{6}{5}+\{\frac{1}{2x}-\frac{1}{6}\}]=\frac{301}{120}$
$\Rightarrow \frac{31}{6}-\frac{6}{5}+\frac{1}{6}-\frac{301}{120}=\frac{195}{120}$
$\Rightarrow x=\frac{120}{2\times 195}=\frac{4}{13}$