If a1,a2,...,an are positive real numbers whose product is a fixed number c, the minimum value of a1+a2+...+an−1+2an is
A
n(2c)1/n
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B
(n+1)c1/n
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C
2nc1/n
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D
(n+1)(2c)1/n
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Solution
The correct option is An(2c)1/n Given that, a1a2...an−1an=c Since, A.M≥G.M Therefore, a1+a2+...+an−1+2ann≥(a1a2...an−12an)1/n ⇒a1+a2+...+an−1+2an≥n(2a1a2...an−1an)1/n ⇒a1+a2+...+an−1+2an≥n(2c)1/n Ans: A