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Question

If a2+ab+b2=19,a4+a2b2+b4=133, then the value of ab is

A
6
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B
7
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C
8
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D
9
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Solution

The correct option is A 6
Given a2+ab+b2=19
a2+b2=19ab
And a4+a2b2+b4=133
a4+b4+2a2b2a2b2=133
(a2+b2)2a2b2=133
Put value a2+b2=19ab
(19ab)2a2b2=133
36138ab+a2b2a2b2=133
38ab=36113338ab=228
ab=6

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