If a=2i+3j+4k,b=i+5j+2k and c=3i+15j+6k, then evaluate ∣∣
∣∣a.aa.ba.cb.ab.bb.cc.ac.bc.c∣∣
∣∣.
A
-1
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B
0
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C
1
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D
None of these
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Solution
The correct option is D 0 We know ∣∣
∣∣a.aa.ba.cb.ab.bb.cc.ac.bc.c∣∣
∣∣=[abc]2=y (say) Given, a=2i+3j+4k,b=i+5j+2k and c=3i+15j+6k Clearly c=3b Hence y=[ab3b]2=9[abb]2=0