If a-b-c-0 then a4-b4-c4-a2b2-b2c2-c2a2 is equal to

The correct option is A 2 a+b+c=0 ⇒ a+b= c ⇒( a+b ) #160; ^ 2 =( c ) #160; ^ 2 ⇒ a ^ 2 + b ^ 2 +2ab= c ^ 2 ⇒ a ^ 2 + b ^ 2 c ^ 2 = ...

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Centroid Formula

If a+b+c=0 ...

Question

If $a + b + c = 0$ then $\frac{a^{4} + b^{4} + c^{4}}{a^{2} b^{2} + b^{2} c^{2} + c^{2} a^{2}}$ is equal to

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If $a + b + c = 0$ then prove

$a^{4} + b^{4} + c^{4} = 2 (a^{2} b^{2} + b^{2} c^{2} + c^{2} a^{2})$

a^{4} + b^{4} + c^{4} \geq a^{2} b^{2} + b^{2} c^{2} + c^{2} a^{2}

Δ A B C

c^{4} - 2 (a^{2} + b^{2}) c^{2} + a^{4} + a^{2} b^{2} + b^{4} = 0

∠ C =

a^{4} - 2 (b^{2} + c^{2}) a^{2} + b^{4} + b^{2} c^{2} + c^{4} = 0

∠ A

60^{\circ}

120^{\circ}

b

a

c

\frac{a^{4} + a^{2} b^{2} + b^{4}}{b^{4} + b^{2} c^{2} + c^{4}} = \frac{a^{2}}{c^{2}}

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