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Question

If a+b+c=0 then the value of (a+b)(b+c)(c+a)abc is

A
1
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B
-1
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C
-3
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D
3
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Solution

The correct option is A -1
Since, a+b+c=0,
So, a+b=c, b+c=a, c+a=b
So, (a+b)(b+c)(c+a)abc=(c)(a)(b)abc=abcabc=1

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