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Question

If a<b<c<d & xϵR then the least value of the function,
f(x)=|xa|+|xb|+|xc|+|xd| is

A
cd+ba
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B
c+dba
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C
c+db+a
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D
cd+b+a
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Solution

The correct option is A c+dba
f(x)=⎪ ⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪ ⎪(a+b+c+d)4xx<a(b+c+d)a2xax<bc+dabbx<c2x(a+b+c)+dcx<d4x(a+b+c+d)xd
We can see that upto b, graph is decreasing and it is constant from b to c and incrasing after c.
Hence, from the graph ,its clear that least value of the function is (c+dab)

120153_126667_ans.png

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