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Question

If A+B+C=π and A,B,C are all greater then 0 and angle C is obtuse then

A
tanAtanB1
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B
tanAtanB <1
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C
tanAtanB=1
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D
None of these
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Solution

The correct option is B tanAtanB <1
A+B=πC
tan(A+B)=tan(πC)=tanC
tanA+tanB1tanAtanB>0 now tanA>0
1tanAtanB>0
or tanAtanB<1

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