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Question

if abc, are different,then the value of x satisfying
∣ ∣0x2ax3bx+a0xcx+bx+c0∣ ∣=0 is

A
a
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B
b
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C
c
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D
0
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Solution

The correct option is A 0
Given, ∣ ∣0x2ax3bx+a0xcx+bx+c0∣ ∣=0
(x2a)(x+b)(xc)+(x3b)(x+a)(x+c)=0
Now, we will check using options.
Option D satisfies above equation.

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