if a≠b≠c, are different,then the value of x satisfying ∣∣
∣∣0x2−ax3−bx+a0x−cx+bx+c0∣∣
∣∣=0 is
A
a
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B
b
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C
c
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D
0
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Solution
The correct option is A0 Given, ∣∣
∣∣0x2−ax3−bx+a0x−cx+bx+c0∣∣
∣∣=0 ⇒(x2−a)(x+b)(x−c)+(x3−b)(x+a)(x+c)=0 Now, we will check using options. Option D satisfies above equation.