If $α$ and $β$ are roots of the quadratic equation $x^{2} - 7 x + 3 = 0$ then the equation whose root are $2 α$ and $2 β$ is

x^{2} + 14 x + 12 = 0

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x^{2} + 14 x - 12 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} - 14 x - 12 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} - 14 x + 12 = 0

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Solution

The correct option is D $x^{2} - 14 x + 12 = 0$
Given equation is:
$x^{2} - 7 x + 3 = 0$
$∴ α + β = 7, α β = 3$
$α' = 2 α, β' = 2 β$
$s' = α' + β' = 2 (α + β) = 14$
$p' = α' β' = 4 α β = 12$
Required equation : $x^{2} - 14 x + 12 = 0$

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