CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If α and β are the roots of the equation ax2+bx+c=0, then the value of limxa[ax2+bx+c+1]2/(xa) is:

A
2a(αβ)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2log|a(αβ)|
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
e2a(αβ)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
ee2|αβ|
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C e2a(αβ)
ax2+bx+c+1=1+a(xα)(xβ)
Put a(xα)(xβ)=y

y0 as xα

Also, 2a(xβ)y=2xα
Thus required limit =limy0[1+y]2a(xβ)y

=limy0[{1+y}1/y]2a(xβ)=e2a(αβ)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature and Location of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon