If α and β are the roots of the equation x2−2x+3=0, then the equation whose roots are α+2,β+2, is
A
x2−6x+11=0
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B
x2−5x+10=0
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C
x2+6x−11=0
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D
None of these
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Solution
The correct option is Ax2−6x+11=0 α and β are the roots of the equation x2−2x+3=0. let y=α+2 ⇒α=y−2 ⇒(y−2)2−2(y−2)+3=0 ⇒y2−6y+11=0 ∴ Equation whose roots are α+2,β+2 is x2−6x+11=0 Hence, option A.