If α,β,γ and δ be four angles of cyclic quadrilateral then the value of cosα+cosβ+cosγ+cosδ is
Since,this is cyclic
quadrilateral then
α+γ=π=β+δ and α+β+γ+δ=2π ...(i)
cosα+cosβ+cosγ+cosδ
=2cosα+γ2cosα−γ2+2cosβ+δ2cosβ−δ2
From eq(i), we get,
=2cosπ2cosα−γ2+2cosπ2cosβ−δ2=0
Hence, option 'B' is correct.