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Question

If α,β,γ are roots of x3+4x+1=0, then (α+β)1+(β+γ)1+(γ+α)1 equals

A
2
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B
3
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C
4
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5
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Solution

The correct option is C 4
We know that If α,β,γ are roots of x3+ax2+bx+c=0, then
(α+β)1+(β+γ)1+(γ+α)1=a2+bcab
Given α,β,γ are the roots of x3+4x+1=0
Here, a=0,b=4,c=1
(α+β)1+(β+γ)1+(γ+α)1=a2+bcab=41

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