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Question

If α=π21 , then sin3αsin7αsin24α+sin14α=

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Solution

The correct option is B 1
sin3αsin7αsin24α+sin14α
=2cos5αsin(2α)2sin19αcos5α
=sin2αsin19α=sin2π21sin19π21
=sin2π21sin(π2π21)=1

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