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Question

If α, β are the roots of the equation ax2+bx+c=0, then the equation whose roots are 1α+β+1α+1β is

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Solution

a+b=ba and ab=ca
1a+β=ab and 1α+1βα+βαβ=bc
Equation is x2(abbc)x+(ab)(bc)=0
bcx2+(b2+ac)x+ab=0

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