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Discriminant

If ax2+bx+1...

Question

If $a x^{2} + b x + 1 = 0, a \in R, b \in R,$ does not have distinct real roots, then the maximum value of $b^{2}$ is

- 4 a

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4 a

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2 a

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- 2 a

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Solution

The correct option is B $4 a$
$T h e e q u a t i o n a x^{2} - b x + 1 = 0 h a s n o d i s t i n c t r e a l r o o t s, T h i s i m p l i e s D = b^{2} - 4 a c \leq 0, b^{2} - 4 a \leq 0 b^{2} \leq 4 a$ .

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