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Question

If b=6[4b+32a5], express a in terms of b.

A
a=33b2(6b)
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B
a=b332(6b)
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C
a=33b2(b6)
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D
none of the above
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Solution

The correct option is A a=33b2(6b)
Given,
b=6[4b+32a5]
=>[4b+32a5]=6b
=>4b+3=(6b)(2a5)
=>4b+3=12a302ab+5b
=>12a332ab+b=0
=>a(122b)=33b
=>2a(6b)=33b
=>a=33b2(6b)

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