If ei- cos- -isin- then for the - ABC- eiA-eiB-eiC is

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If eiθ= cos...

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If $e^{i θ} = c o s θ + i s i n θ$ then for the $Δ A B C, e^{i A} . e^{i B} . e^{i C}$ is

- i

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e^{i θ} = c o s θ + i s i n θ

△ A B C, e^{i A} . e^{i B} . e^{i C}

e^{i θ} = c o s θ + i s i n θ,

△ A B C

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∣ \frac{2 i z_{i} - z_{i} - z_{2}}{2 i z_{1} + z_{1} + z_{2}} ∣=∣ \frac{c o s θ + i s i n θ}{c o s θ - i s i n θ} ∣

\frac{z_{1}}{z_{2}}

A + B + C = π, e^{i θ} = cos θ + i sin θ

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For $z = x + i y$ , where $x, y \in R$ and $i = \sqrt{- 1}$ , what is the polar form of representation?

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