If f:[−15,15]→R, defined by f(x)=[x2a]sinx+cosx ( where [⋅] denotes greatest integer function) is an even function then set of values of a belongs in interval
A
(225,∞)
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B
R
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C
(0,225)
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D
ϕ
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Solution
The correct option is A(225,∞)
Note that, if [x2a]≥1 then f(x)=ksin(x)+cos(x), where k is an positive integer greater than 1.
Then in this case, the function will not be an even function for any value of a.
Hence the function will be an even function if and only if [x2a]=0