CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

If f:RR defined by f(x)=2x23x+5, then find the value of f(x+h)f(x)h at h0

A
4x+2h
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4x+2h-3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4x-2h+3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4x-2h-3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 4x+2h-3
Given, f(x)=2x23x+5
So, f(x+h)f(x)h=2(x+h)23(x+h)+5(2x23x+5)h
=2x2+2h2+4xh3x3h+52x2+3x5h=2h2+4xh3hh=2h+4x3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon