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Question

If f:RR defined by f(x)=2x23x+5, then find the value of f(x+h)f(x)h at h0

A
4x+2h
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B
4x+2h-3
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C
4x-2h+3
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D
4x-2h-3
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Solution

The correct option is C 4x+2h-3
Given, f(x)=2x23x+5
So, f(x+h)f(x)h=2(x+h)23(x+h)+5(2x23x+5)h
=2x2+2h2+4xh3x3h+52x2+3x5h=2h2+4xh3hh=2h+4x3

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