If 1-1-2x1-3x -A-1-2x-B-1-3x then 2B-

The correct option is D 3A LHS=1(1 2x)(1+3x); #160; RHS=A(1 2x)+B(1+3x) =A(1+3x)+B(1 2x)(1 2x)(1+3x) LHS=RHS 1=A(1+3x)+B(1 2x) keep x ...

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Integration by Partial Fractions

If 1/1-2x1+...

Question

If $\frac{1}{(1 - 2 x) (1 + 3 x)}$ $= \frac{A}{1 - 2 x} + \frac{B}{1 + 3 x}$ then $2 B =$

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-3A

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Solution

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Similar questions

\frac{(1 + x) (1 + 2 x) (1 + 3 x)}{(1 - x) (1 - 2 x) (1 - 3 x)} = K +

\frac{A}{1 - x} + \frac{B}{1 - 2 x} + \frac{C}{1 - 3 x}

f (x) =

∣ ∣ ∣ ∣ ∣ \begin{matrix} (1 + 3 x)^{2 a} & (1 + 2 x)^{3 b} & 1 1 & (1 + 3 x)^{2 a} & (1 + 2 x)^{3 b} (1 + 2 x)^{3 b} & 1 & (1 + 3 x)^{2 a} \end{matrix} ∣ ∣ ∣ ∣ ∣

a, b, c

\frac{1}{(1 - x) (1 - 2 x) (1 - 3 x)} = \frac{a}{1 - x} + \frac{b}{1 - 2 x} + \frac{c}{1 - 3 x}

\frac{a}{1} + \frac{b}{3} + \frac{c}{5} =

f (x) = \frac{x}{1 + x} + \frac{x}{(1 + x) (1 + 2 x)} + \frac{x}{(1 + 2 x) (1 + 3 x)} + . . . . \infty

Choose the correct answer.

If a, b, c, are in A.P., then the determinant

A. 0 B. 1 C. x D. 2x

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