Question

If $\frac{1+3p}{3},\frac{1-p}{4}$ and $\frac{1-2p}{2}$ are the probabilities of the three mutually exclusive events, then $p\in$

• A. $[0,1]$
• B. $[0,\frac{1}{2}]$
• C. $[\frac{1}{3},1]$
• D. $[\frac{1}{3},\frac{1}{2}]$

Answer 1

The correct option is D $[\frac{1}{3},\frac{1}{2}]$