If 1 - 4 10h - 3 - 2 h-1 - 2 - 3 9 - 2 h -6- what is the value of h

The correct option is B 15 / 8 Given equation is: 14(10h) 32(h+1)= 23(92h)+6 10h4 3h2 32 = 9h3+6 5h2 3h2 32 = 3h+6 h= 3h+6+32 4h= ...

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Byju's Answer

Standard IX

Mathematics

Subtraction of Polynomials

If 1 / 4 10...

Question

If $\frac{1}{4} (10 h) - \frac{3}{2} (h + 1) = - \frac{2}{3} (\frac{9}{2} h) + 6$ , what is the value of h

\frac{9}{8}

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\frac{15}{8}

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There is no value of h for which the equation is true.

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There are infinitely many values of h for which the equation is true.

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Solution

The correct option is B $\frac{15}{8}$
Given equation is:
$\frac{1}{4} (10 h) - \frac{3}{2} (h + 1) = - \frac{2}{3} (\frac{9}{2} h) + 6$

$⟹ \frac{10 h}{4} - \frac{3 h}{2} - \frac{3}{2} = - \frac{9 h}{3} + 6$

$⟹ \frac{5 h}{2} - \frac{3 h}{2} - \frac{3}{2} = - 3 h + 6$

$⟹ h = - 3 h + 6 + \frac{3}{2}$

$⟹ 4 h = \frac{15}{2}$

$⟹ h = \frac{15}{8}$

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If 14(10h)−32(h+1)=−23(92h)+6, what is the value of h

The correct option is B 158Given equation is:14(10h)−32(h+1)=−23(92h)+6⟹10h4−3h2−32=−9h3+6⟹5h2−3h2−32=−3h+6⟹h=−3h+6+32⟹4h=152⟹h=158

If $\frac{1}{4} (10 h) - \frac{3}{2} (h + 1) = - \frac{2}{3} (\frac{9}{2} h) + 6$ , what is the value of h