If 1-k-1-3-1-4 then the value of K is

The correct option is A 15/7 1/k=1/3+1/4 Multiply by k ∴ 1=k/3+k/4 ⇒ 12=4k+3k ⇒ 7k=12 ⇒ k=157 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Types of Fractions

If 1/k=1/3+...

Question

If $\frac{1}{k} = \frac{1}{3} + \frac{1}{4}$ then the value of K is

1 \frac{5}{7}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 \frac{5}{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 \frac{5}{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 \frac{5}{12}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

1 + \frac{4}{7} + \frac{9}{7^{2}} + \frac{16}{7^{3}} + \frac{25}{7^{4}} +

k

a_{k} = cos (\frac{k π}{7}) + i sin (\frac{k π}{7})

\frac{12 \sum k = 1 | a_{k + 1} - a_{k} |}{3 \sum k = 1 | a_{4 k - 1} - a_{4 k - 2} |}

If the point (2k – 3, k + 2) lies on the line 2x + 3y + 15 = 0, find the value of k.

lim n \to \infty \frac{(1^{2} + 2^{2} + . . . . . . . + n^{2}) (1^{4} + 2^{4} + . . . . . . . + n^{4})}{(1^{7} + 2^{7} + . . . . + n^{7})} = \frac{K + 1}{15};

Δ A B C; \frac{cos A}{7} = \frac{cos B}{19} = \frac{cos C}{25} = k

∣ ∣ ∣ ∣ ∣ \begin{matrix} - 1 / k & 25 & 19 25 & - 1 / k & 7 19 & 7 & - 1 / k \end{matrix} ∣ ∣ ∣ ∣ ∣ =

Join BYJU'S Learning Program