Question

If $\frac{1}{{\log }_3\pi }+\frac{1}{{\log }_4\pi }>x$, then $x$ is

• A. $2$
• B. $3$
• C. $3.5$
• D. $\pi$

Answer 1

The correct option is A $2$

Let $y=\frac{1}{{\log }_3\pi }+\frac{1}{{\log }_4\pi }$

$={\log }_{\pi }3+{\log }_{\pi }4$

$y={\log }_{\pi }12$

${\pi }^y=12$

We know, $12>{\pi }^2$

$\Rightarrow y>{\log }_{\pi }{\pi }^2=2$