If 25 - t-4-5-3- 10 - t-8 t - 0 is m2 t4- then the value of m is

25 × t^ 45^ 3× 10 × t^ 8= 25 × 5^310× t^ 4 + 8 = 5 × 5^32× t^4 = #160; 6252 t^4 ...

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Byju's Answer

Standard IX

Mathematics

Laws of Exponents for Real Numbers

If 25 × t-4...

Question

If $\frac{25 \times t^{- 4}}{5^{- 3} \times 10 \times t^{- 8}} (t \neq 0)$ is $\frac{m}{2} t^{4}$ , then the value of $m$ is

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Solution

$\frac{25 \times t^{- 4}}{5^{- 3} \times 10 \times t^{- 8}} = \frac{25 \times 5^{3}}{10} \times t^{- 4 + 8}$
$= \frac{5 \times 5^{3}}{2} \times t^{4}$
$= \frac{625}{2} t^{4}$

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If 25×t−45−3×10×t−8(t≠0) is m2t4, then the value of m is

25×t−45−3×10×t−8=25×5310×t−4+8=5×532×t4=6252t4

If $\frac{25 \times t^{- 4}}{5^{- 3} \times 10 \times t^{- 8}} (t \neq 0)$ is $\frac{m}{2} t^{4}$ , then the value of $m$ is

$\frac{25 \times t^{- 4}}{5^{- 3} \times 10 \times t^{- 8}} = \frac{25 \times 5^{3}}{10} \times t^{- 4 + 8}$
$= \frac{5 \times 5^{3}}{2} \times t^{4}$
$= \frac{625}{2} t^{4}$