If 32-500 - 32-22 - 5m- then the value of m is -

The correct option is B 3 We can write it as, 32/500 =2^5/2^2×5^3 On comparing with 2^5/2^2×5^m we get, nbsp; m=3 ...

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Product Law

If 32/500 =...

Question

If $\frac{32}{500} = \frac{32}{(2)^{2} \times (5)^{m}}$ , then the value of $m$ is :

2

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{(\frac{5}{3})}^{2} \times {(\frac{5}{3})}^{2} = \frac{625}{m}

m

\frac{1^{2} + 2^{2}}{3!} + \frac{1^{2} + 2^{2} + 3^{2}}{4!} + \frac{1^{2} + 2^{2} + 3^{2} + 4^{2}}{5!} + . . . . . .

n

\frac{3}{1^{2} \times 2^{2}} + \frac{5}{2^{2} \times 3^{2}} + \frac{7}{3^{2} \times 4^{2}} + \dots \dots

0.99

n

n

\frac{3}{1^{2} \times 2^{2}} + \frac{5}{2^{2} \times 3^{2}} + \frac{7}{3^{2} \times 4^{2}} + \dots \dots

0.99

n

\frac{1 \times 2^{2} + 2 \times 3^{2} + 3 \times 4^{2} + \dots + n (n + 1)^{2}}{1^{2} \times 2 + 2^{2} \times 3 + 3^{2} \times 4 + \dots + n^{2} (n + 1)} = \frac{8}{7}

n =

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