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B
−154
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C
−74
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D
−14
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Solution
The correct option is A−12 3x+4(x+1)2(x−1)=Ax−1+Bx+1+C(x+1)2 3x+4(x+1)2(x−1)=A(x+1)2+B(x2−1)+C(x−1)(x+1)2(x−1) ⇒3x+4=A(x+1)2+B(x2−1)+C(x−1) When x=1,7=4A,A=74 When x=−1,−2C=1,C=−12