If 3x-5y-5z-3y-x-5z-y-5x-y-z-x-z the show that every ratio is equal to x-y-

Given, 3x 5y/5z+3y=x+5z/y 5x=y z/x z ⇒3x 5y/5z+3y = x+5z/y 5x = 5y 5z/5x 5z = 3x 5y+x+5z+5y 5z/5z+3y+y 5x+5x 5z = 4x/4y = x/y #160; ...

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Introduction to Ratio

If 3x-5y/5z...

Question

If $\frac{3 x - 5 y}{5 z + 3 y} = \frac{x + 5 z}{y - 5 x} = \frac{y - z}{x - z}$ the show that every ratio is equal to $\frac{x}{y}$ .

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Solution

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Similar questions

(\frac{2}{5} \frac{y}{z} + \frac{2}{5} \frac{z}{x})

(\frac{2}{5} \frac{z}{x} + \frac{2}{5} \frac{x}{y})

(\frac{2}{5} \frac{x}{y} + \frac{2}{5} \frac{y}{z})

\frac{2 x - 3 y}{3 z + y} = \frac{z - y}{z - x} = \frac{x + 3 z}{2 y - 3 x}

= \frac{x}{y}

\frac{5 x - 3}{x} + \frac{5 y - 3}{y} + \frac{5 z - 3}{z} = 0

\frac{1}{x} + \frac{1}{y} + \frac{1}{z}

α

x + 3 y + 5 z = α x

5 x + y + 3 z = α y

3 x + 5 y + z = α z

\frac{y - z}{a (b - c)} = \frac{z - x}{b (c - a)} = \frac{x - y}{c (a - b)}

\frac{x}{3 x - y - z} = \frac{y}{3 y - z - x} = \frac{z}{3 z - x - y}

x + y + z \neq 0

\frac{a x + b y}{x + y} = \frac{b x + a z}{x + z} = \frac{a y + b z}{y + z}

x + y + z \neq 0

\frac{a + b}{2}

\frac{y + z}{a} = \frac{z + x}{b} = \frac{x + y}{c}

\frac{x}{b + c - a} = \frac{y}{c + a - b} = \frac{z}{a + b - c}

\frac{3 x - 5 y}{5 z + 3 y} = \frac{x + 5 z}{y - 5 x} = \frac{y - z}{x - z}

\frac{x}{y}

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