If 5 z2-7 z1 is purely imaginary- then - 2z1 - 3z2-2z1 - 3z2 - is equal to

The correct option is C none of these 5 z_2/7 z_1 is purely imaginary ⇒5z_2/7z_1 = k #160; #160;i , where k ε R ⇒z_2/z_1 = 7 ki/5 Now, ...

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Modulus of a Complex Number

If 5 z2/7 z...

Question

If $\frac{5 z_{2}}{7 z_{1}}$ is purely imaginary, then $∣ ∣ ∣ \frac{2 z_{1} + 3 z_{2}}{2 z_{1} - 3 z_{2}} ∣ ∣ ∣$ is equal to

5/7

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7/9

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25/49

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none of these

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