If 7x-2-6-x-4-3-x-3-3- then x-

The correct option is A 4/3 Given. 7x+2/6 x 4/3=x+3/3 .Multiply throughout by 3 , we get ∴ 7x+2/2 (x 4)=x+3 ∴ 7x+2/2=2x 1 O ...

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Standard VI

Mathematics

Proportions

If 7x+2/6-x...

Question

If $\frac{7 x + 2}{6} - \frac{x - 4}{3} = \frac{x + 3}{3}$ , then $x =$

- \frac{4}{3}

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\frac{1}{3}

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\frac{- 1}{3}

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1 \frac{1}{3}

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Solution

The correct option is A $- \frac{4}{3}$
Given. $\frac{7 x + 2}{6} - \frac{x - 4}{3} = \frac{x + 3}{3}$ .
Multiply throughout by $3$ , we get
$∴$ $\frac{7 x + 2}{2} - (x - 4) = x + 3$
$∴$ $\frac{7 x + 2}{2} = 2 x - 1$
On cross multiplying, we get
$3 x = - 4$
$∴$ $x = \frac{- 4}{3}$

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If 7x+26−x−43=x+33, then x=

The correct option is A −43Given. 7x+26−x−43=x+33.Multiply throughout by 3, we get∴ 7x+22−(x−4)=x+3∴ 7x+22=2x−1On cross multiplying, we get3x=−4∴ x=−43

If $\frac{7 x + 2}{6} - \frac{x - 4}{3} = \frac{x + 3}{3}$ , then $x =$

The correct option is A $- \frac{4}{3}$
Given. $\frac{7 x + 2}{6} - \frac{x - 4}{3} = \frac{x + 3}{3}$ .
Multiply throughout by $3$ , we get
$∴$ $\frac{7 x + 2}{2} - (x - 4) = x + 3$
$∴$ $\frac{7 x + 2}{2} = 2 x - 1$
On cross multiplying, we get
$3 x = - 4$
$∴$ $x = \frac{- 4}{3}$